Solution
Solution
+1
Solution steps
Apply trig inverse properties
Solve
Solve
Show solutions in decimal form
Popular Examples
tan(θ)=(-4.86)/(14.56)12cos(x)+5sin(x)=32cos(x)sin^2(x)=cos(x)2cos(4θ)=-1,0<= θ<= 2pi1*sin(45)=1.57*sin(θ)
Frequently Asked Questions (FAQ)
What is the general solution for sin(2θ)=0.4905 ?
The general solution for sin(2θ)=0.4905 is θ=(0.51266…)/2+pin,θ= pi/2-(0.51266…)/2+pin