What is the general solution for (sin(x))/(2-2sin^2(x))=0 ?

The general solution for (sin(x))/(2-2sin^2(x))=0 is x=2pin,x=pi+2pin

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(sin(x))/(2-2sin^2(x))=0

\frac{sin ( x )}{2 - 2 sin ^{2} ( x )} = 0

x = 2 πn, x = π + 2 πn

Solution steps

\frac{sin ( x )}{2 - 2 sin ^{2} ( x )} = 0

Solve by substitution

sin (x) = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn

tan (θ) = 3, 0 \leq θ < 2 π

0 = - cos (8 x) + cos (2 x)

3 cos^{2} (x) + cos (x) - 2 = 0, 0 \leq x \leq 2 π

- 1 = tan^{2} (θ)

y, x = - cos (y)

What is the general solution for (sin(x))/(2-2sin^2(x))=0 ?
The general solution for (sin(x))/(2-2sin^2(x))=0 is x=2pin,x=pi+2pin