What is the general solution for -2tan(θ)-4-tan^2(θ)=-3 ?

The general solution for -2tan(θ)-4-tan^2(θ)=-3 is θ=(3pi)/4+pin

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-2tan(θ)-4-tan^2(θ)=-3

- 2 tan (θ) - 4 - tan^{2} (θ) = - 3

θ = \frac{3 π}{4} + πn

Solution steps

- 2 tan (θ) - 4 - tan^{2} (θ) = - 3

Solve by substitution

tan (θ) = - 1

tan (θ) = - 1 : θ = \frac{3 π}{4} + πn

Combine all the solutions

θ = \frac{3 π}{4} + πn

cos^{2} (x) = 3 - 5 cos (x)

sin (x) = \frac{1}{sec ( x )}

x, 1 - 2 cos^{2} (x) - 2 cos (x) = 0

1 = tan (\frac{x}{3})

cos (12 x) = 0

What is the general solution for -2tan(θ)-4-tan^2(θ)=-3 ?
The general solution for -2tan(θ)-4-tan^2(θ)=-3 is θ=(3pi)/4+pin