What is the general solution for 2|sin(4x)|=0 ?

The general solution for 2|sin(4x)|=0 is x=(pin)/2 ,x= pi/4+(pin)/2

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2|sin(4x)|=0

2 ∣ sin (4 x) ∣ = 0

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

Solution steps

2 ∣ sin (4 x) ∣ = 0

Divide both sides by

2

∣ sin (4 x) ∣ = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

sin (4 x) = 0

General solutions for

sin (4 x) = 0

4 x = 0 + 2 πn, 4 x = π + 2 πn

Solve

4 x = 0 + 2 πn : x = \frac{πn}{2}

Solve

4 x = π + 2 πn : x = \frac{π}{4} + \frac{πn}{2}

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

sin (α) = - \frac{3}{5}

sin (2 x) = \frac{2 \cdot ( 1 \cdot 1 0 ^{12} )}{( 1 \cdot 1 0 ^{7} ) ^{2}}

1 + sin (θ) = \frac{( 3 + 2 )}{2}

- cos (θ) = - cos (2 θ)

cos (x) = \frac{4}{3.3 8 ^{2} + 4 ^{2}}

What is the general solution for 2|sin(4x)|=0 ?
The general solution for 2|sin(4x)|=0 is x=(pin)/2 ,x= pi/4+(pin)/2