What is the general solution for 2cos(4x)+5=6 ?

The general solution for 2cos(4x)+5=6 is x= pi/(12)+(pin)/2 ,x=(5pi}{12}+\frac{pin)/2

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2cos(4x)+5=6

2 cos (4 x) + 5 = 6

x = \frac{π}{12} + \frac{πn}{2}, x = \frac{5 π}{12} + \frac{πn}{2}

Solution steps

2 cos (4 x) + 5 = 6

Move

5

to the right side

2 cos (4 x) = 1

Divide both sides by

2

cos (4 x) = \frac{1}{2}

General solutions for

cos (4 x) = \frac{1}{2}

4 x = \frac{π}{3} + 2 πn, 4 x = \frac{5 π}{3} + 2 πn

Solve

4 x = \frac{π}{3} + 2 πn : x = \frac{π}{12} + \frac{πn}{2}

Solve

4 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{12} + \frac{πn}{2}

x = \frac{π}{12} + \frac{πn}{2}, x = \frac{5 π}{12} + \frac{πn}{2}

cos (2 θ) = - \frac{3}{2}, 0 \leq θ \leq 2 π

2 cos^{2} (a) = 1 + cos (12 0^{\circ})

cos (x) = \frac{11}{17 \cdot 38}

\frac{sin ( 9 0 ^{\circ} )}{5.8} = \frac{sin ( x )}{5}

sin (x) tan (x) + 3 sin (x) = 0

What is the general solution for 2cos(4x)+5=6 ?
The general solution for 2cos(4x)+5=6 is x= pi/(12)+(pin)/2 ,x=(5pi}{12}+\frac{pin)/2