What is the general solution for tan(2x)=0.32 ?

The general solution for tan(2x)=0.32 is x=(0.30970…)/2+(pin)/2

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tan(2x)=0.32

tan (2 x) = 0.32

x = \frac{0.30970 \dots}{2} + \frac{πn}{2}

Solution steps

tan (2 x) = 0.32

Apply trig inverse properties

2 x = arctan (0.32) + πn

Solve

2 x = arctan (0.32) + πn : x = \frac{arctan ( 0.32 )}{2} + \frac{πn}{2}

x = \frac{arctan ( 0.32 )}{2} + \frac{πn}{2}

Show solutions in decimal form

x = \frac{0.30970 \dots}{2} + \frac{πn}{2}

sin (x) = \frac{- 3}{2}, 27 0^{\circ} < x < 36 0^{\circ}

x, R = \frac{v ^{2} sin ( 2 x )}{g}

sin (θ) csc (3 θ - 40) = 1, c a l c u l e tan (3 θ)

3 cot^{2} (x) - 4 cot (x) + 3 = 0

cos^{2} (x) + 5 cos (x) - 6 = 0

What is the general solution for tan(2x)=0.32 ?
The general solution for tan(2x)=0.32 is x=(0.30970…)/2+(pin)/2