What is the general solution for -4+sin(-3x+(2pi)/3)=-4 ?

The general solution for -4+sin(-3x+(2pi)/3)=-4 is x=-(2pin)/3+(2pi)/9 ,x=-pi/3+(2pi)/9-(2pin)/3

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-4+sin(-3x+(2pi)/3)=-4

- 4 + sin (- 3 x + \frac{2 π}{3}) = - 4

x = - \frac{2 πn}{3} + \frac{2 π}{9}, x = - \frac{π}{3} + \frac{2 π}{9} - \frac{2 πn}{3}

Solution steps

- 4 + sin (- 3 x + \frac{2 π}{3}) = - 4

Add

4

to both sides

- 4 + sin (- 3 x + \frac{2 π}{3}) + 4 = - 4 + 4

Simplify

sin (- 3 x + \frac{2 π}{3}) = 0

General solutions for

sin (- 3 x + \frac{2 π}{3}) = 0

- 3 x + \frac{2 π}{3} = 0 + 2 πn, - 3 x + \frac{2 π}{3} = π + 2 πn

Solve

- 3 x + \frac{2 π}{3} = 0 + 2 πn : x = - \frac{2 πn}{3} + \frac{2 π}{9}

Solve

- 3 x + \frac{2 π}{3} = π + 2 πn : x = - \frac{π}{3} + \frac{2 π}{9} - \frac{2 πn}{3}

x = - \frac{2 πn}{3} + \frac{2 π}{9}, x = - \frac{π}{3} + \frac{2 π}{9} - \frac{2 πn}{3}

2 \cdot sin (x) \cdot cos (x) = cos (x)

sin (2 θ) = \frac{- 2 6}{7}

x, sin (x) = - \frac{7}{25}

\frac{1}{tan ( α )} + tan (α) = \frac{1}{sin ( α )}

tan (2 θ) = \frac{- 81}{81}

What is the general solution for -4+sin(-3x+(2pi)/3)=-4 ?
The general solution for -4+sin(-3x+(2pi)/3)=-4 is x=-(2pin)/3+(2pi)/9 ,x=-pi/3+(2pi)/9-(2pin)/3