What is the general solution for 0=(sin(x))^2 ?

The general solution for 0=(sin(x))^2 is x=2pin,x=pi+2pin

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0=(sin(x))^2

0 = (sin (x))^{2}

x = 2 πn, x = π + 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

0 = (sin (x))^{2}

Switch sides

(sin (x))^{2} = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

sec^{2} (x) - tan^{2} (x) = cos (x)

x, cos^{2} (x) - sin^{2} (x) = 0

cos (x) = \frac{60}{61}, cos (2 x)

x, tan (3 x) = - \frac{1}{3}

arcsin (\frac{x}{3 ^{2} + x ^{2}}) = 0.01117

What is the general solution for 0=(sin(x))^2 ?
The general solution for 0=(sin(x))^2 is x=2pin,x=pi+2pin