What is the general solution for -sin^2(x)+cos^2(x)=1 ?

The general solution for -sin^2(x)+cos^2(x)=1 is x=pin

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-sin^2(x)+cos^2(x)=1

- sin^{2} (x) + cos^{2} (x) = 1

x = πn

Solution steps

- sin^{2} (x) + cos^{2} (x) = 1

Rewrite using trig identities

cos (2 x) = 1

General solutions for

cos (2 x) = 1

2 x = 0 + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

x = πn

tan^{2} (x) - 4 sec (x) = 4

sin (x + 1 0^{\circ}) = - tan (1 5^{\circ})

tan (2 θ) = \frac{73 - 8}{- 10}

x, T (7) = 3.15 cos (\frac{π}{6} x) + 19.15

tan (x) = \frac{- 3}{1}

What is the general solution for -sin^2(x)+cos^2(x)=1 ?
The general solution for -sin^2(x)+cos^2(x)=1 is x=pin