What is the general solution for (((sin(x))))/((a))=k ?

The general solution for (((sin(x))))/((a))=k is x=arcsin(ka)+2pin,x=pi+arcsin(-ka)+2pin

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(((sin(x))))/((a))=k

\frac{( ( sin ( x ) ) )}{( a )} = k

x = arcsin (ka) + 2 πn, x = π + arcsin (- ka) + 2 πn

Solution steps

\frac{( ( sin ( x ) ) )}{( a )} = k

Multiply both sides by

a

sin (x) = ka; a \neq = 0

Apply trig inverse properties

x = arcsin (ka) + 2 πn, x = π + arcsin (- ka) + 2 πn

sin (θ) = \frac{2}{2}, 0 \leq θ < 2 π

x, 10 (cos (x))^{2} + 5 cos (x) - 5 = 0

1 - \frac{cos ^{2} ( x )}{1 + sin ( x )} = 2 cos (x)

cos (x) = \frac{4}{14}

\frac{sin ( 57.2 2 ^{\circ} )}{31.5} = \frac{sin ( θ )}{24.4}

What is the general solution for (((sin(x))))/((a))=k ?
The general solution for (((sin(x))))/((a))=k is x=arcsin(ka)+2pin,x=pi+arcsin(-ka)+2pin