What is the general solution for picos(2θ)=0 ?

The general solution for picos(2θ)=0 is θ= pi/4+pin,θ=(3pi)/4+pin

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picos(2θ)=0

π cos (2 θ) = 0

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

Solution steps

π cos (2 θ) = 0

Divide both sides by

π

cos (2 θ) = 0

General solutions for

cos (2 θ) = 0

2 θ = \frac{π}{2} + 2 πn, 2 θ = \frac{3 π}{2} + 2 πn

Solve

2 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{4} + πn

Solve

2 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{4} + πn

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

2 + 3 sec (x) - 4 cos (x) = 23

4 sin (x) \cdot cos (x) = 2 sin (x)

- 1 sec^{2} (θ) + 2 sec (θ) = 1

cos (θ) = 0.8701

cos (3 v) = cos (6), 0^{\circ} \leq v^{\circ} \leq 36 0^{\circ}

What is the general solution for picos(2θ)=0 ?
The general solution for picos(2θ)=0 is θ= pi/4+pin,θ=(3pi)/4+pin