What is the general solution for 2sin(2x)=1,interval(0,360) ?

The general solution for 2sin(2x)=1,interval(0,360) is No Solution for x\in\mathbb{R}

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2sin(2x)=1,interval(0,360)

2 sin (2 x) = 1, in t er v a l (0, 36 0^{\circ})

No Solution for x \in R

Solution steps

2 sin (2 x) = 1, in t er v a l (0, 36 0^{\circ})

Divide both sides by

2

sin (2 x) = \frac{1}{2}

General solutions for

sin (2 x) = \frac{1}{2}

2 x = 3 0^{\circ} + 36 0^{\circ} n, 2 x = 15 0^{\circ} + 36 0^{\circ} n

Solve

2 x = 3 0^{\circ} + 36 0^{\circ} k : x = 1 5^{\circ} + 18 0^{\circ} k

Solve

2 x = 15 0^{\circ} + 36 0^{\circ} k : x = 7 5^{\circ} + 18 0^{\circ} k

x = 1 5^{\circ} + 18 0^{\circ} k, x = 7 5^{\circ} + 18 0^{\circ} k

Solutions for the range

in t er v a l (0, 36 0^{\circ})

No Solution for x \in R

sinh (x + 1) = 0

sin (a) = 0.6542

0 = - 6 sin (3 x)

tan (x) = 4 - 3 cot (x)

tan (x) = 193.661

What is the general solution for 2sin(2x)=1,interval(0,360) ?
The general solution for 2sin(2x)=1,interval(0,360) is No Solution for x\in\mathbb{R}