What is the general solution for (sec(x))/(cos(x))-1=0 ?

The general solution for (sec(x))/(cos(x))-1=0 is x=2pin,x=pi+2pin

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(sec(x))/(cos(x))-1=0

\frac{sec ( x )}{cos ( x )} - 1 = 0

x = 2 πn, x = π + 2 πn

Solution steps

\frac{sec ( x )}{cos ( x )} - 1 = 0

Simplify

\frac{sec ( x )}{cos ( x )} - 1 : \frac{sec ( x ) - cos ( x )}{cos ( x )}

\frac{sec ( x ) - cos ( x )}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

sec (x) - cos (x) = 0

Rewrite using trig identities

- \frac{1}{sec ( x )} + sec (x) = 0

Solve by substitution

sec (x) = 1, sec (x) = - 1

sec (x) = 1 : x = 2 πn

sec (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn

- 9 (sin (x))^{2} + 2 sin (x) + 2 = 0

cos^{2} (x) - 2 cos (x) + 1 = 0, 0^{\circ} 36 0^{\circ}

sin^{4} (x) = sin^{2} (x), 0 \leq x < 2 π

sin (θ) - 0.1 cos (θ) = \frac{6.88}{9.8}

sin (x) = 0.3352

What is the general solution for (sec(x))/(cos(x))-1=0 ?
The general solution for (sec(x))/(cos(x))-1=0 is x=2pin,x=pi+2pin