What is the general solution for cos^2(2x)-sin^2(2x)=1 ?

The general solution for cos^2(2x)-sin^2(2x)=1 is x=(pin)/2

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cos^2(2x)-sin^2(2x)=1

cos^{2} (2 x) - sin^{2} (2 x) = 1

x = \frac{πn}{2}

Solution steps

cos^{2} (2 x) - sin^{2} (2 x) = 1

Rewrite using trig identities

cos (2 \cdot 2 x) = 1

General solutions for

cos (2 \cdot 2 x) = 1

2 \cdot 2 x = 0 + 2 πn

Solve

2 \cdot 2 x = 0 + 2 πn : x = \frac{πn}{2}

x = \frac{πn}{2}

sin^{4} (x) = - \frac{1}{8}

sin (θ) = 0.321

sin (x + 7 5^{\circ}) = \frac{3}{2}

tan (\frac{x}{6}) + 3 = 0

A, (1 + tan (A)) (1 + tan (B)) = 2

What is the general solution for cos^2(2x)-sin^2(2x)=1 ?
The general solution for cos^2(2x)-sin^2(2x)=1 is x=(pin)/2