What is the general solution for cos(θ)= 2/5 ,cot(θ)<0 ?

The general solution for cos(θ)= 2/5 ,cot(θ)<0 is No Solution for θ\in\mathbb{R}

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cos(θ)= 2/5 ,cot(θ)<0

cos (θ) = \frac{2}{5}, cot (θ) < 0

No Solution for θ \in R

Solution steps

cos (θ) = \frac{2}{5}, cot (θ) < 0

Apply trig inverse properties

cos (θ) = \frac{2}{5}

General solutions for

cos (θ) = \frac{2}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{2}{5}) + 2 πn, θ = 2 π - arccos (\frac{2}{5}) + 2 πn

θ = arccos (\frac{2}{5}) + 2 πn, θ = 2 π - arccos (\frac{2}{5}) + 2 πn

Solutions for the range

cot (θ) < 0

No Solution for θ \in R

θ, cos (θ) = \frac{2}{2}

b, s (t) = tan (b t^{2})

tan (x) = \frac{80}{90}

- \frac{5}{4} = cos (x)

sin (2 x) = cos^{2} (x)

What is the general solution for cos(θ)= 2/5 ,cot(θ)<0 ?
The general solution for cos(θ)= 2/5 ,cot(θ)<0 is No Solution for θ\in\mathbb{R}