What is the general solution for solvefor t,a=5*sin(t) ?

The general solution for solvefor t,a=5*sin(t) is t=arcsin(a/5)+2pin,t=pi+arcsin(-a/5)+2pin

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solvefor t,a=5*sin(t)

solve for

t, a = 5 \cdot sin (t)

t = arcsin (\frac{a}{5}) + 2 πn, t = π + arcsin (- \frac{a}{5}) + 2 πn

Solution steps

a = 5 sin (t)

Switch sides

5 sin (t) = a

Divide both sides by

5

sin (t) = \frac{a}{5}

Apply trig inverse properties

t = arcsin (\frac{a}{5}) + 2 πn, t = π + arcsin (- \frac{a}{5}) + 2 πn

cos^{(2)} (x) = \frac{( 3 ( 1 - sin ( x ) ) )}{( 2 )}

\frac{1}{2} sin (\frac{x}{5}) = 0

sin (\frac{1}{3} x) = 0, 0 \leq x \leq 10 π

sin (π y) = cos (1) sin (\frac{π}{6}) - \frac{1}{2}

0 = 4 cos (120 x)

What is the general solution for solvefor t,a=5*sin(t) ?
The general solution for solvefor t,a=5*sin(t) is t=arcsin(a/5)+2pin,t=pi+arcsin(-a/5)+2pin