What is the general solution for -2=-2sec(x)+tan^2(x) ?

The general solution for -2=-2sec(x)+tan^2(x) is x=2pin

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-2=-2sec(x)+tan^2(x)

- 2 = - 2 sec (x) + tan^{2} (x)

x = 2 πn

Solution steps

- 2 = - 2 sec (x) + tan^{2} (x)

Switch sides

- 2 sec (x) + tan^{2} (x) = - 2

Subtract

- 2

from both sides

- 2 sec (x) + tan^{2} (x) + 2 = 0

Rewrite using trig identities

1 + sec^{2} (x) - 2 sec (x) = 0

Solve by substitution

sec (x) = 1

sec (x) = 1 : x = 2 πn

Combine all the solutions

x = 2 πn

tan^{2} (y) + 1 = cos^{2} (y)

4 sin (2 x) + csc (2 x) = 4

cot (θ) = \frac{9}{40}

sin (a) = - \frac{1}{2}

5 cos (x) - 2 sin (x) = 0.5

What is the general solution for -2=-2sec(x)+tan^2(x) ?
The general solution for -2=-2sec(x)+tan^2(x) is x=2pin