What is the general solution for 5cos(x)+sqrt(2)=3cos(x),0<= x<= 2pi ?

The general solution for 5cos(x)+sqrt(2)=3cos(x),0<= x<= 2pi is x=(3pi)/4 ,x=(5pi)/4

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5cos(x)+sqrt(2)=3cos(x),0<= x<= 2pi

5 cos (x) + 2 = 3 cos (x), 0 \leq x \leq 2 π

x = \frac{3 π}{4}, x = \frac{5 π}{4}

Solution steps

5 cos (x) + 2 = 3 cos (x), 0 \leq x \leq 2 π

Solve by substitution

cos (x) = - \frac{2}{2}

cos (x) = - \frac{2}{2}, 0 \leq x \leq 2 π : x = \frac{3 π}{4}, x = \frac{5 π}{4}

Combine all the solutions

x = \frac{3 π}{4}, x = \frac{5 π}{4}

2 tan (2 x + 10) = - 5.5

sin (t) = sin (2 t)

\frac{3}{2} = cos (x)

tan (x + \frac{π}{6}) = \frac{2}{3}

4 cos^{2} (x) + 4 sin (x) - 5 = 0

What is the general solution for 5cos(x)+sqrt(2)=3cos(x),0<= x<= 2pi ?
The general solution for 5cos(x)+sqrt(2)=3cos(x),0<= x<= 2pi is x=(3pi)/4 ,x=(5pi)/4