What is the general solution for solvefor x,-1*(cos(x))/(sin(x))=0 ?

The general solution for solvefor x,-1*(cos(x))/(sin(x))=0 is x= pi/2+pin

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solvefor x,-1*(cos(x))/(sin(x))=0

solve for

x, - 1 \cdot \frac{cos ( x )}{sin ( x )} = 0

x = \frac{π}{2} + πn

Degrees

x = 9 0^{\circ} + 18 0^{\circ} n

Solution steps

- 1 \cdot \frac{cos ( x )}{sin ( x )} = 0

Rewrite using trig identities

- 1 \cdot \frac{cos ( x )}{sin ( x )}

Use the basic trigonometric identity:

\frac{cos ( x )}{sin ( x )} = cot (x)

= - 1 \cdot cot (x)

- 1 \cdot cot (x) = 0

Divide both sides by

- 1

- 1 \cdot cot (x) = 0

Divide both sides by

- 1

\frac{- 1 \cdot cot ( x )}{- 1} = \frac{0}{- 1}

Simplify

cot (x) = 0

cot (x) = 0

General solutions for

cot (x) = 0

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

x = \frac{π}{2} + πn

x = \frac{π}{2} + πn

8 cos (θ) - 4 = 0

2 (1 + cos (θ)) = 0

0 = cos (π x) \cdot π + sin (π x) π

\frac{sin ( x )}{2} = 1

x, tan (x) = - 3

What is the general solution for solvefor x,-1*(cos(x))/(sin(x))=0 ?
The general solution for solvefor x,-1*(cos(x))/(sin(x))=0 is x= pi/2+pin