What is the general solution for sin(θ)= 4/5 ,0<θ< pi/2 ,cos(2) ?

The general solution for sin(θ)= 4/5 ,0<θ< pi/2 ,cos(2) is θ=0.92729…

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sin(θ)= 4/5 ,0<θ< pi/2 ,cos(2)

sin (θ) = \frac{4}{5}, 0 < θ < \frac{π}{2}, cos (2)

θ = 0.92729 \dots

Degrees

θ = 53.13010 \dots^{\circ}

Solution steps

sin (θ) = \frac{4}{5}, 0 < θ < \frac{π}{2}, cos (2)

Apply trig inverse properties

sin (θ) = \frac{4}{5}

General solutions for

sin (θ) = \frac{4}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{4}{5}) + 2 πn, θ = π - arcsin (\frac{4}{5}) + 2 πn

θ = arcsin (\frac{4}{5}) + 2 πn, θ = π - arcsin (\frac{4}{5}) + 2 πn

Solutions for the range

0 < θ < \frac{π}{2}

θ = arcsin (\frac{4}{5})

Show solutions in decimal form

θ = 0.92729 \dots

25 (sec^{2} (5 x)) = 0

tan (θ) = (\frac{5}{0})

cos (C) = \frac{5 ^{2} + 4.0 5 ^{2} - 3 ^{2}}{2 \cdot ( 4.05 \cdot 5 )}

- 1 + sin (x) = - 1.3

\frac{sin ( x )}{45} = \frac{sin ( 3 5 ^{\circ} )}{30}

What is the general solution for sin(θ)= 4/5 ,0<θ< pi/2 ,cos(2) ?
The general solution for sin(θ)= 4/5 ,0<θ< pi/2 ,cos(2) is θ=0.92729…