What is the general solution for 4sin^2(x-60)=3 ?

The general solution for 4sin^2(x-60)=3 is x=120+360n,x=360n+180,x=360n+300,x=360n+360

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4sin^2(x-60)=3

4 sin^{2} (x - 6 0^{\circ}) = 3

x = 12 0^{\circ} + 36 0^{\circ} n, x = 36 0^{\circ} n + 18 0^{\circ}, x = 36 0^{\circ} n + 30 0^{\circ}, x = 36 0^{\circ} n + 36 0^{\circ}

Solution steps

4 sin^{2} (x - 6 0^{\circ}) = 3

Solve by substitution

sin (x - 6 0^{\circ}) = \frac{3}{2}, sin (x - 6 0^{\circ}) = - \frac{3}{2}

sin (x - 6 0^{\circ}) = \frac{3}{2} : x = 12 0^{\circ} + 36 0^{\circ} n, x = 36 0^{\circ} n + 18 0^{\circ}

sin (x - 6 0^{\circ}) = - \frac{3}{2} : x = 36 0^{\circ} n + 30 0^{\circ}, x = 36 0^{\circ} n + 36 0^{\circ}

Combine all the solutions

x = 12 0^{\circ} + 36 0^{\circ} n, x = 36 0^{\circ} n + 18 0^{\circ}, x = 36 0^{\circ} n + 30 0^{\circ}, x = 36 0^{\circ} n + 36 0^{\circ}

cos (a) = - \frac{4}{5}, 9 0^{\circ} < a < 18 0^{\circ}

3 cot^{2} (2 x - \frac{3 π}{2}) = 1

1.6 sin (θ) = 1.49

cos (x) = 0.695

3 + sec (x) = 5

What is the general solution for 4sin^2(x-60)=3 ?
The general solution for 4sin^2(x-60)=3 is x=120+360n,x=360n+180,x=360n+300,x=360n+360