What is the general solution for 3cos(5t)=0 ?

The general solution for 3cos(5t)=0 is t= pi/(10)+(2pin)/5 ,t=(3pi}{10}+\frac{2pin)/5

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3cos(5t)=0

3 cos (5 t) = 0

t = \frac{π}{10} + \frac{2 πn}{5}, t = \frac{3 π}{10} + \frac{2 πn}{5}

Solution steps

3 cos (5 t) = 0

Divide both sides by

3

cos (5 t) = 0

General solutions for

cos (5 t) = 0

5 t = \frac{π}{2} + 2 πn, 5 t = \frac{3 π}{2} + 2 πn

Solve

5 t = \frac{π}{2} + 2 πn : t = \frac{π}{10} + \frac{2 πn}{5}

Solve

5 t = \frac{3 π}{2} + 2 πn : t = \frac{3 π}{10} + \frac{2 πn}{5}

t = \frac{π}{10} + \frac{2 πn}{5}, t = \frac{3 π}{10} + \frac{2 πn}{5}

cos^{2} (9 0^{\circ} - θ) = 1872

cos (x) - cos (x) = 0

sin (x + 1) = cos (x)

3 cos (x) - 2 = 1

sin (4 x) = - sin (2 x)

What is the general solution for 3cos(5t)=0 ?
The general solution for 3cos(5t)=0 is t= pi/(10)+(2pin)/5 ,t=(3pi}{10}+\frac{2pin)/5