What is the general solution for -10sin^2(t)=0 ?

The general solution for -10sin^2(t)=0 is t=2pin,t=pi+2pin

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-10sin^2(t)=0

- 10 sin^{2} (t) = 0

t = 2 πn, t = π + 2 πn

Solution steps

- 10 sin^{2} (t) = 0

Divide both sides by

- 10

sin (t) = 0

General solutions for

sin (t) = 0

t = 0 + 2 πn, t = π + 2 πn

Solve

t = 0 + 2 πn : t = 2 πn

t = 2 πn, t = π + 2 πn

x, e^{y} cos (2 x) + y = 1

cos (θ) = 0.4, sec (θ)

- \frac{π}{2} sin (\frac{π x}{2}) = 0

cot (θ) = \frac{1 + cos ^{2} ( θ )}{2 sin ( θ ) cos ( θ )}

cot (x) = 3 + 1

What is the general solution for -10sin^2(t)=0 ?
The general solution for -10sin^2(t)=0 is t=2pin,t=pi+2pin