What is the general solution for 7cos(θ)=sqrt(2)+9cos(θ) ?

The general solution for 7cos(θ)=sqrt(2)+9cos(θ) is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin

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7cos(θ)=sqrt(2)+9cos(θ)

7 cos (θ) = 2 + 9 cos (θ)

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solution steps

7 cos (θ) = 2 + 9 cos (θ)

Solve by substitution

cos (θ) = - \frac{2}{2}

cos (θ) = - \frac{2}{2} : θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Combine all the solutions

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

sec (x) \cdot cot (x) - 2 cot (x) + sec (x) = 2

3 sin^{2} (x) - 10 sin (x) - 8 = 0

2 \cdot 9.8 \cdot L (1 - cos (θ)) = 0.018

cos (7 x) = sin (4 x + 2)

12 cos (β) - 5 sin (β) = 4.7

What is the general solution for 7cos(θ)=sqrt(2)+9cos(θ) ?
The general solution for 7cos(θ)=sqrt(2)+9cos(θ) is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin