What is the general solution for arctan(θ)= 6/8 ?

The general solution for arctan(θ)= 6/8 is θ=tan(3/4)

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arctan(θ)= 6/8

arctan (θ) = \frac{6}{8}

θ = tan (\frac{3}{4})

Solution steps

arctan (θ) = \frac{6}{8}

Cancel the common factor:

2

arctan (θ) = \frac{3}{4}

Apply trig inverse properties

θ = tan (\frac{3}{4})

4 cos^{2} (x) - 7 cos (x) + 3 = 0

tan (θ) = \frac{- \frac{4}{3} - ( - \frac{11}{3} )}{1 + ( - \frac{4}{3} ) ( - \frac{11}{3} )}

8 + 2 cot (x) = 12

(1 + cot (p)) tan (p) = 3

csc (θ + π) = - \frac{2 3}{3}

What is the general solution for arctan(θ)= 6/8 ?
The general solution for arctan(θ)= 6/8 is θ=tan(3/4)