What is the general solution for solvefor c,2=4sin(0.5(0-c))+2 ?

The general solution for solvefor c,2=4sin(0.5(0-c))+2 is c=-4pin,c=-2pi-4pin

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solvefor c,2=4sin(0.5(0-c))+2

solve for

c, 2 = 4 sin (0.5 (0 - c)) + 2

c = - 4 πn, c = - 2 π - 4 πn

Solution steps

2 = 4 sin (0.5 (0 - c)) + 2

Switch sides

4 sin (0.5 (0 - c)) + 2 = 2

Subtract

2

from both sides

4 sin (0.5 (0 - c)) + 2 - 2 = 2 - 2

Simplify

4 sin (0.5 (0 - c)) = 0

Divide both sides by

4

sin (0.5 (0 - c)) = 0

General solutions for

sin (0.5 (0 - c)) = 0

0.5 (0 - c) = 0 + 2 πn, 0.5 (0 - c) = π + 2 πn

Solve

0.5 (0 - c) = 0 + 2 πn : c = - 4 πn

Solve

0.5 (0 - c) = π + 2 πn : c = - 2 π - 4 πn

c = - 4 πn, c = - 2 π - 4 πn

3 cos^{2} (x) - 23 cos (x) = cos (x)

196 sin (θ) - 49 cos (θ) = 160

4 tan (x) + 3 = - 7

8 tan (θ) + 15 = 0

cos (x) = \frac{48.4}{54.5}

What is the general solution for solvefor c,2=4sin(0.5(0-c))+2 ?
The general solution for solvefor c,2=4sin(0.5(0-c))+2 is c=-4pin,c=-2pi-4pin