What is the general solution for (cos(x)-1)(tan(x)-1)=0 ?

The general solution for (cos(x)-1)(tan(x)-1)=0 is x=2pin,x= pi/4+pin

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(cos(x)-1)(tan(x)-1)=0

(cos (x) - 1) (tan (x) - 1) = 0

x = 2 πn, x = \frac{π}{4} + πn

Solution steps

(cos (x) - 1) (tan (x) - 1) = 0

Solving each part separately

cos (x) - 1 = 0 or tan (x) - 1 = 0

cos (x) - 1 = 0 : x = 2 πn

tan (x) - 1 = 0 : x = \frac{π}{4} + πn

Combine all the solutions

x = 2 πn, x = \frac{π}{4} + πn

- cos (2 x + 3) = 0

tan (2 x) = \frac{- 270 - 120}{130}

cos^{2} (θ) = \frac{2 - 3}{4}

sin (2 x) = \frac{π}{6}

sin (x) = \frac{8}{17} sin (2 x)

What is the general solution for (cos(x)-1)(tan(x)-1)=0 ?
The general solution for (cos(x)-1)(tan(x)-1)=0 is x=2pin,x= pi/4+pin