What is the general solution for 2=1+sin(2x) ?

The general solution for 2=1+sin(2x) is x= pi/4+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2=1+sin(2x)

2 = 1 + sin (2 x)

x = \frac{π}{4} + πn

Solution steps

2 = 1 + sin (2 x)

Switch sides

1 + sin (2 x) = 2

Move

1

to the right side

sin (2 x) = 1

General solutions for

sin (2 x) = 1

2 x = \frac{π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

cosh (x - 1) = 2

tan (x) = \frac{7}{25}

tan (x) = - 1, 0 < x < 2 π

sec^{2} (x) - 2 = tan^{2} (x), 0 \leq x \leq 2 π

sin (\frac{1}{2} x) = - \frac{1}{2}

What is the general solution for 2=1+sin(2x) ?
The general solution for 2=1+sin(2x) is x= pi/4+pin