What is the general solution for cos(t)= 3/5 ,0<t< pi/2 ?

The general solution for cos(t)= 3/5 ,0<t< pi/2 is t=0.92729…

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cos(t)= 3/5 ,0<t< pi/2

cos (t) = \frac{3}{5}, 0 < t < \frac{π}{2}

t = 0.92729 \dots

Solution steps

cos (t) = \frac{3}{5}, 0 < t < \frac{π}{2}

Apply trig inverse properties

t = arccos (\frac{3}{5}) + 2 πn, t = 2 π - arccos (\frac{3}{5}) + 2 πn

Solutions for the range

0 < t < \frac{π}{2}

t = arccos (\frac{3}{5})

Show solutions in decimal form

t = 0.92729 \dots

cos (x) = \frac{- 2}{2}

y, - ln (cos (x)) = - 2 cos (x) \cdot sin (y)

2 sin (a) + csc (a) = 3

cos (x) = \frac{- 2}{7}

csc (x) = \frac{9}{17}

What is the general solution for cos(t)= 3/5 ,0<t< pi/2 ?
The general solution for cos(t)= 3/5 ,0<t< pi/2 is t=0.92729…