What is the general solution for -3sin(3x)=1 ?

The general solution for -3sin(3x)=1 is x=-(0.33983…)/3+(2pin)/3 ,x= pi/3+(0.33983…)/3+(2pin)/3

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-3sin(3x)=1

- 3 sin (3 x) = 1

x = - \frac{0.33983 \dots}{3} + \frac{2 πn}{3}, x = \frac{π}{3} + \frac{0.33983 \dots}{3} + \frac{2 πn}{3}

Solution steps

- 3 sin (3 x) = 1

Divide both sides by

- 3

sin (3 x) = - \frac{1}{3}

Apply trig inverse properties

3 x = arcsin (- \frac{1}{3}) + 2 πn, 3 x = π + arcsin (\frac{1}{3}) + 2 πn

Solve

3 x = arcsin (- \frac{1}{3}) + 2 πn : x = - \frac{arcsin ( \frac{1}{3} )}{3} + \frac{2 πn}{3}

Solve

3 x = π + arcsin (\frac{1}{3}) + 2 πn : x = \frac{π}{3} + \frac{arcsin ( \frac{1}{3} )}{3} + \frac{2 πn}{3}

x = - \frac{arcsin ( \frac{1}{3} )}{3} + \frac{2 πn}{3}, x = \frac{π}{3} + \frac{arcsin ( \frac{1}{3} )}{3} + \frac{2 πn}{3}

Show solutions in decimal form

x = - \frac{0.33983 \dots}{3} + \frac{2 πn}{3}, x = \frac{π}{3} + \frac{0.33983 \dots}{3} + \frac{2 πn}{3}

\frac{1}{cos ( x ) - cos ( x )} = sin (x) tan (x)

cos (θ) = \frac{3}{5} (270360)

2 sin (x) = tan (x) cos (x) - cos (x)

x, z = 3 - sin (2 x + y)

tan (x) = \frac{27}{48}

What is the general solution for -3sin(3x)=1 ?
The general solution for -3sin(3x)=1 is x=-(0.33983…)/3+(2pin)/3 ,x= pi/3+(0.33983…)/3+(2pin)/3