What is the general solution for 2sqrt(2)cos(θ)-2=0 ?

The general solution for 2sqrt(2)cos(θ)-2=0 is θ= pi/4+2pin,θ=(7pi)/4+2pin

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2sqrt(2)cos(θ)-2=0

22 cos (θ) - 2 = 0

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Solution steps

22 cos (θ) - 2 = 0

Move

2

to the right side

22 cos (θ) = 2

Divide both sides by

22

cos (θ) = \frac{2}{2}

General solutions for

cos (θ) = \frac{2}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

tan (x) = \frac{22}{326}

3 cos (6 x) = 2

2 cos (t) = 1 + sin (t)

cos (θ) = - \frac{5}{6}, csc (θ)

sin^{2} (x) = - 2 + 3 sin (x) + cos^{2} (x)

What is the general solution for 2sqrt(2)cos(θ)-2=0 ?
The general solution for 2sqrt(2)cos(θ)-2=0 is θ= pi/4+2pin,θ=(7pi)/4+2pin