What is the general solution for sin(x)= 4/5 , pi/2 <= x<= pi ?

The general solution for sin(x)= 4/5 , pi/2 <= x<= pi is x=pi-0.92729…

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sin(x)= 4/5 , pi/2 <= x<= pi

sin (x) = \frac{4}{5}, \frac{π}{2} \leq x \leq π

x = π - 0.92729 \dots

Solution steps

sin (x) = \frac{4}{5}, \frac{π}{2} \leq x \leq π

Apply trig inverse properties

x = arcsin (\frac{4}{5}) + 2 πn, x = π - arcsin (\frac{4}{5}) + 2 πn

Solutions for the range

\frac{π}{2} \leq x \leq π

x = π - arcsin (\frac{4}{5})

Show solutions in decimal form

x = π - 0.92729 \dots

2 - 2 cosh (t - 2) = 0

cos (x) = \frac{1}{37}

\frac{sin ( 2 x )}{cos ( x )} = 4 + sin (2 x) \cdot tan (x)

sin (x) = 0.2174

x, arccot (x^{2}) y = arccot (x^{2})

What is the general solution for sin(x)= 4/5 , pi/2 <= x<= pi ?
The general solution for sin(x)= 4/5 , pi/2 <= x<= pi is x=pi-0.92729…