What is the general solution for 2sin^2(x)+5sin(x)=0 ?

The general solution for 2sin^2(x)+5sin(x)=0 is x=2pin,x=pi+2pin

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2sin^2(x)+5sin(x)=0

2 sin^{2} (x) + 5 sin (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

2 sin^{2} (x) + 5 sin (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = - \frac{5}{2}

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = - \frac{5}{2} :

No Solution

Combine all the solutions

x = 2 πn, x = π + 2 πn

cos (2 x) - 7 cos (x) - 3 = 0

tan^{2} (4 5^{\circ} - \frac{x}{3}) = 0.58

- 20 csc (x) = 40

0 = 4 ∣ sin (6 θ) ∣

5 sin^{2} (θ) - 11 sin (θ) + 6 = 0

What is the general solution for 2sin^2(x)+5sin(x)=0 ?
The general solution for 2sin^2(x)+5sin(x)=0 is x=2pin,x=pi+2pin