What is the general solution for cot^{(2)}(x)+2cot(x)+1=0 ?

The general solution for cot^{(2)}(x)+2cot(x)+1=0 is x=(3pi)/4+pin

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cot^{(2)}(x)+2cot(x)+1=0

cot^{(2)} (x) + 2 cot (x) + 1 = 0

x = \frac{3 π}{4} + πn

Solution steps

cot^{(2)} (x) + 2 cot (x) + 1 = 0

Solve by substitution

cot (x) = - 1

cot (x) = - 1 : x = \frac{3 π}{4} + πn

Combine all the solutions

x = \frac{3 π}{4} + πn

cos (x) cos (x) = \frac{( 1 - sin ^{2} ( x ) )}{sin ( x )}

r^{2} = a^{2} (sin (x) + cos (x))

sec (x) - 2 = 0, 0 \leq x \leq 2 π

(cos (t) - 3) (2 sin^{2} (t) - 1) = 0

cot (x) = 3.2404

What is the general solution for cot^{(2)}(x)+2cot(x)+1=0 ?
The general solution for cot^{(2)}(x)+2cot(x)+1=0 is x=(3pi)/4+pin