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Popular >

r=a(1+sin(x))

Solution

r = a (1 + sin (x))

Solution

x = arcsin (\frac{r}{a} - 1) + 2 πn, x = π + arcsin (- \frac{r}{a} + 1) + 2 πn

Solution steps

r = a (1 + sin (x))

Switch sides

a (1 + sin (x)) = r

Divide both sides by

a; a \neq = 0

1 + sin (x) = \frac{r}{a}; a \neq = 0

Move

1

to the right side

sin (x) = \frac{r}{a} - 1; a \neq = 0

Apply trig inverse properties

x = arcsin (\frac{r}{a} - 1) + 2 πn, x = π + arcsin (- \frac{r}{a} + 1) + 2 πn

Popular Examples

cos(2x)-sin^2(x)-1=3sin(x)

cos (2 x) - sin^{2} (x) - 1 = 3 sin (x)

tan(Θ)=1.4,180<,Θ<270

tan (Θ) = 1.4, 18 0^{\circ} <, Θ < 27 0^{\circ}

(1+4cos(θ))^2=(sqrt(3)sin(θ))

(1 + 4 cos (θ))^{2} = (3 sin (θ))

sin(θ)-(cos(θ))/5 =0.6377

sin (θ) - \frac{cos ( θ )}{5} = 0.6377

cos(2θ)=0.4,0<= θ<= 360

cos (2 θ) = 0.4, 0^{\circ} \leq θ \leq 36 0^{\circ}

Frequently Asked Questions (FAQ)

What is the general solution for r=a(1+sin(x)) ?
The general solution for r=a(1+sin(x)) is x=arcsin(r/a-1)+2pin,x=pi+arcsin(-r/a+1)+2pin