What is the general solution for cos^2(θ)=2cos(θ) ?

The general solution for cos^2(θ)=2cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin

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cos^2(θ)=2cos(θ)

cos^{2} (θ) = 2 cos (θ)

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

cos^{2} (θ) = 2 cos (θ)

Solve by substitution

cos (θ) = 2, cos (θ) = 0

cos (θ) = 2 :

No Solution

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

2 sin (x) - sin (2 x) = sin (2 x)

2 cos^{2} (x) + cos (2 x) - 2 = 0

3 cos (x) + 5 = 7, 0^{\circ} \leq x \leq 36 0^{\circ}

cot (3 x - 6^{\circ}) = \frac{3}{3}

sec (x) = 4

What is the general solution for cos^2(θ)=2cos(θ) ?
The general solution for cos^2(θ)=2cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin