What is the value of (tan(30)+tan(60))/(1-tan(30)tan(60)) ?

The value of (tan(30)+tan(60))/(1-tan(30)tan(60)) is Undefined

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(tan(30)+tan(60))/(1-tan(30)tan(60))

\frac{tan ( 3 0 ^{\circ} ) + tan ( 6 0 ^{\circ} )}{1 - tan ( 3 0 ^{\circ} ) tan ( 6 0 ^{\circ} )}

Undefined

Solution steps

\frac{tan ( 3 0 ^{\circ} ) + tan ( 6 0 ^{\circ} )}{1 - tan ( 3 0 ^{\circ} ) tan ( 6 0 ^{\circ} )}

Use the following trivial identity:

tan (3 0^{\circ}) = \frac{3}{3}

tan (3 0^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= \frac{3}{3}

Use the following trivial identity:

tan (6 0^{\circ}) = 3

tan (6 0^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 3

= \frac{\frac{3}{3} + 3}{1 - \frac{3}{3} 3}

= Undefined

sin (arccos (\frac{2}{3}) - arctan (\frac{1}{2}))

cos (7 5^{\circ}) cos (1 5^{\circ}) - sin (7 5^{\circ}) sin (1 5^{\circ})

\frac{22}{tan ( 1 2 ^{\circ} )}

cos (arctan (- \frac{2}{3}))

sin (3 0^{\circ}) \cdot 5

What is the value of (tan(30)+tan(60))/(1-tan(30)tan(60)) ?
The value of (tan(30)+tan(60))/(1-tan(30)tan(60)) is Undefined