What is the general solution for (9tan(θ))/(10-tan^2(θ))=1 ?

The general solution for (9tan(θ))/(10-tan^2(θ))=1 is θ=-1.47112…+pin,θ= pi/4+pin

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(9tan(θ))/(10-tan^2(θ))=1

\frac{9 tan ( θ )}{10 - tan ^{2} ( θ )} = 1

θ = - 1.47112 \dots + πn, θ = \frac{π}{4} + πn

Solution steps

\frac{9 tan ( θ )}{10 - tan ^{2} ( θ )} = 1

Solve by substitution

tan (θ) = - 10, tan (θ) = 1

tan (θ) = - 10 : θ = arctan (- 10) + πn

tan (θ) = 1 : θ = \frac{π}{4} + πn

Combine all the solutions

θ = arctan (- 10) + πn, θ = \frac{π}{4} + πn

Show solutions in decimal form

θ = - 1.47112 \dots + πn, θ = \frac{π}{4} + πn

tan (x) = \frac{0.45 \cdot cos ( 5 ^{\circ} )}{1 - 0.45 \cdot sin ( 5 ^{\circ} )}

6 sin (2 x) = 3 cos (3 0^{\circ})

cos (y) = - 1

cot (x) = - \frac{2}{3}

tan (\frac{3 θ}{4}) = \frac{- 3}{3}

What is the general solution for (9tan(θ))/(10-tan^2(θ))=1 ?
The general solution for (9tan(θ))/(10-tan^2(θ))=1 is θ=-1.47112…+pin,θ= pi/4+pin