What is the general solution for 2sqrt(3)cos(θ/2)=-3 ?

The general solution for 2sqrt(3)cos(θ/2)=-3 is θ=(5pi)/3+4pin,θ=(7pi)/3+4pin

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2sqrt(3)cos(θ/2)=-3

23 cos (\frac{θ}{2}) = - 3

θ = \frac{5 π}{3} + 4 πn, θ = \frac{7 π}{3} + 4 πn

Solution steps

23 cos (\frac{θ}{2}) = - 3

Divide both sides by

23

cos (\frac{θ}{2}) = - \frac{3}{2}

General solutions for

cos (\frac{θ}{2}) = - \frac{3}{2}

\frac{θ}{2} = \frac{5 π}{6} + 2 πn, \frac{θ}{2} = \frac{7 π}{6} + 2 πn

Solve

\frac{θ}{2} = \frac{5 π}{6} + 2 πn : θ = \frac{5 π}{3} + 4 πn

Solve

\frac{θ}{2} = \frac{7 π}{6} + 2 πn : θ = \frac{7 π}{3} + 4 πn

θ = \frac{5 π}{3} + 4 πn, θ = \frac{7 π}{3} + 4 πn

\frac{1}{cos ^{2} ( \frac{θ}{2} )} = 12 cos (θ)

3 cos (x) - sin (x) = 2

cos (x) = \frac{34}{70}

x, z = cos (x^{2} + 2 y)

- 3 sin (t) + 4 cos (t) = 0

What is the general solution for 2sqrt(3)cos(θ/2)=-3 ?
The general solution for 2sqrt(3)cos(θ/2)=-3 is θ=(5pi)/3+4pin,θ=(7pi)/3+4pin