What is the general solution for solvefor x,cos^2(x)=2-2sin(x) ?

The general solution for solvefor x,cos^2(x)=2-2sin(x) is x= pi/2+2pin

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solvefor x,cos^2(x)=2-2sin(x)

solve for

x, cos^{2} (x) = 2 - 2 sin (x)

x = \frac{π}{2} + 2 πn

Solution steps

cos^{2} (x) = 2 - 2 sin (x)

Subtract

2 - 2 sin (x)

from both sides

cos^{2} (x) - 2 + 2 sin (x) = 0

Rewrite using trig identities

- 1 - sin^{2} (x) + 2 sin (x) = 0

Solve by substitution

sin (x) = 1

sin (x) = 1 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn

x, 2 \cdot 2.25 \cdot cos (x) = 0

x, 2 sin (x) = 1

cot (x) + 2 cos (x) = 0

2 cot (θ) - 1 = 2, cot (θ) - 1 = 0

2 cos^{2} (a) - 7 cos (a) + 3 = 0

What is the general solution for solvefor x,cos^2(x)=2-2sin(x) ?
The general solution for solvefor x,cos^2(x)=2-2sin(x) is x= pi/2+2pin