What is the general solution for 6sin(b)+sqrt(12)=0 ?

The general solution for 6sin(b)+sqrt(12)=0 is b=-0.61547…+2pin,b=pi+0.61547…+2pin

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6sin(b)+sqrt(12)=0

6 sin (b) + 12 = 0

b = - 0.61547 \dots + 2 πn, b = π + 0.61547 \dots + 2 πn

Solution steps

6 sin (b) + 12 = 0

12 = 23

6 sin (b) + 23 = 0

Move

23

to the right side

6 sin (b) = - 23

Divide both sides by

6

sin (b) = - \frac{3}{3}

Apply trig inverse properties

b = arcsin (- \frac{3}{3}) + 2 πn, b = π + arcsin (\frac{3}{3}) + 2 πn

Show solutions in decimal form

b = - 0.61547 \dots + 2 πn, b = π + 0.61547 \dots + 2 πn

40 + 40 cos (\frac{2 π x}{9}) = 50

tan (x) + sec (x) - 1 = 0

sin (x) (sin (x) - 1) = 3 cos^{2} (x)

1 = 1 + sec (x)

x, cos^{2} (x) = 4 p + 6

What is the general solution for 6sin(b)+sqrt(12)=0 ?
The general solution for 6sin(b)+sqrt(12)=0 is b=-0.61547…+2pin,b=pi+0.61547…+2pin