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受欢迎的三角函数 >

solvefor θ,(90^2)/(250(32.2))=tan(θ)

解答

求解

θ, \frac{9 0 ^{2}}{250 ( 32.2 )} = tan (θ)

解答

θ = 0.78849 \dots + πn

+1

度数

θ = 45.17738 \dots^{\circ} + 18 0^{\circ} n

求解步骤

\frac{9 0 ^{2}}{250 ( 32.2 )} = tan (θ)

交换两边

tan (θ) = \frac{9 0 ^{2}}{250 \cdot 32.2}

化简

\frac{9 0 ^{2}}{250 \cdot 32.2} : \frac{162}{161}

\frac{9 0 ^{2}}{250 \cdot 32.2}

数字相乘:

250 \cdot 32.2 = 8050

= \frac{9 0 ^{2}}{8050}

分解

9 0^{2} : 3^{4} \cdot 2^{2} \cdot 5^{2}

因式分解

90 = 3^{2} \cdot 2 \cdot 5

= (3^{2} \cdot 2 \cdot 5)^{2}

使用指数法则:

(ab)^{c} = a^{c} b^{c}

= 2^{2} \cdot 5^{2} (3^{2})^{2}

化简

(3^{2})^{2} : 3^{4}

(3^{2})^{2}

使用指数法则:

(a^{b})^{c} = a^{b c}

= 3^{2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= 3^{4}

= 3^{4} \cdot 2^{2} \cdot 5^{2}

分解

8050 : 5^{2} \cdot 2 \cdot 7 \cdot 23

因式分解

8050 = 5^{2} \cdot 2 \cdot 7 \cdot 23

= \frac{3 ^{4} \cdot 2 ^{2} \cdot 5 ^{2}}{5 ^{2} \cdot 2 \cdot 7 \cdot 23}

消掉

\frac{2 ^{2} \cdot 3 ^{4} \cdot 5 ^{2}}{2 \cdot 5 ^{2} \cdot 7 \cdot 23} : \frac{3 ^{4} \cdot 2}{7 \cdot 23}

\frac{2 ^{2} \cdot 3 ^{4} \cdot 5 ^{2}}{2 \cdot 5 ^{2} \cdot 7 \cdot 23}

约分:

2

= \frac{3 ^{4} \cdot 5 ^{2} \cdot 2}{5 ^{2} \cdot 7 \cdot 23}

约分:

5^{2}

= \frac{3 ^{4} \cdot 2}{7 \cdot 23}

= \frac{3 ^{4} \cdot 2}{7 \cdot 23}

数字相乘:

7 \cdot 23 = 161

= \frac{3 ^{4} \cdot 2}{161}

3^{4} \cdot 2 = 162

3^{4} \cdot 2

3^{4} = 81

= 81 \cdot 2

数字相乘:

81 \cdot 2 = 162

= 162

= \frac{162}{161}

使用反三角函数性质

tan (θ) = \frac{162}{161}

tan (θ) = \frac{162}{161}

的通解

tan (x) = a \Rightarrow x = arctan (a) + πn

θ = arctan (\frac{162}{161}) + πn

θ = arctan (\frac{162}{161}) + πn

以小数形式表示解

θ = 0.78849 \dots + πn

作图

流行的例子

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