What is the general solution for solvefor x,arccos(e^{-x})= pi/3 ?

The general solution for solvefor x,arccos(e^{-x})= pi/3 is x=ln(2)

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solvefor x,arccos(e^{-x})= pi/3

solve for

x, arccos (e^{- x}) = \frac{π}{3}

x = ln (2)

Solution steps

arccos (e^{- x}) = \frac{π}{3}

Apply trig inverse properties

e^{- x} = \frac{1}{2}

Solve

e^{- x} = \frac{1}{2} : x = ln (2)

x = ln (2)

2 cos^{2} (4 x + 1) = 0

x, 2 sin (x) = - 1

t, f = a cos (\frac{t π}{6} - \frac{11 π}{12})

- 9 cos^{2} (θ) + 9 = 16 sin (θ) - 7, 0 \leq θ < 36 0^{\circ}

\frac{cos ( x )}{sin ^{2} ( x )} = \frac{2}{3}

What is the general solution for solvefor x,arccos(e^{-x})= pi/3 ?
The general solution for solvefor x,arccos(e^{-x})= pi/3 is x=ln(2)