What is the general solution for sin(x)=-1/3 ,0<= x<= 2pi ?

The general solution for sin(x)=-1/3 ,0<= x<= 2pi is x=pi+0.33983…,x=-0.33983…+2pi

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sin(x)=-1/3 ,0<= x<= 2pi

sin (x) = - \frac{1}{3}, 0 \leq x \leq 2 π

x = π + 0.33983 \dots, x = - 0.33983 \dots + 2 π

Solution steps

sin (x) = - \frac{1}{3}, 0 \leq x \leq 2 π

Apply trig inverse properties

x = arcsin (- \frac{1}{3}) + 2 πn, x = π + arcsin (\frac{1}{3}) + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = π + arcsin (\frac{1}{3}), x = - arcsin (\frac{1}{3}) + 2 π

Show solutions in decimal form

x = π + 0.33983 \dots, x = - 0.33983 \dots + 2 π

3 csc (x) = 2 tan (x)

3 = 6 cos (x)

2 cos (a) \cdot sin (2 a) - 1 + 2 sin (2 a) - cos (a) = 0

a, \frac{8 0 ^{2} sin ( 2 a )}{9.8} = 350

tan (A) = \frac{5}{12}, b = 3

What is the general solution for sin(x)=-1/3 ,0<= x<= 2pi ?
The general solution for sin(x)=-1/3 ,0<= x<= 2pi is x=pi+0.33983…,x=-0.33983…+2pi