What is the general solution for 3cos(x)-1=4cos(x) ?

The general solution for 3cos(x)-1=4cos(x) is x=pi+2pin

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3cos(x)-1=4cos(x)

3 cos (x) - 1 = 4 cos (x)

x = π + 2 πn

Solution steps

3 cos (x) - 1 = 4 cos (x)

Solve by substitution

cos (x) = - 1

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = π + 2 πn

sin (x) = 666

- 2 cot (θ) = cot^{2} (θ) + 1

[sin (4 x) cos (x) - cos (4 x) sin (x)]^{2} = 1

cos (θ) = \frac{202}{331 \cdot 2 33}

5 sin (θ) + 12 cos (θ) = 13

What is the general solution for 3cos(x)-1=4cos(x) ?
The general solution for 3cos(x)-1=4cos(x) is x=pi+2pin