What is the general solution for 2cos(5x)=0 ?

The general solution for 2cos(5x)=0 is x= pi/(10)+(2pin)/5 ,x=(3pi}{10}+\frac{2pin)/5

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2cos(5x)=0

2 cos (5 x) = 0

x = \frac{π}{10} + \frac{2 πn}{5}, x = \frac{3 π}{10} + \frac{2 πn}{5}

Solution steps

2 cos (5 x) = 0

Divide both sides by

2

cos (5 x) = 0

General solutions for

cos (5 x) = 0

5 x = \frac{π}{2} + 2 πn, 5 x = \frac{3 π}{2} + 2 πn

Solve

5 x = \frac{π}{2} + 2 πn : x = \frac{π}{10} + \frac{2 πn}{5}

Solve

5 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{10} + \frac{2 πn}{5}

x = \frac{π}{10} + \frac{2 πn}{5}, x = \frac{3 π}{10} + \frac{2 πn}{5}

sin (θ) = - \frac{5}{4}

2 sin^{2} (\frac{x}{2}) + cos (x) = 1 + sin (x)

5 sin^{2} (x) - 6 sin (x) cos (x) = 0

10 sin (20 t - \frac{π}{6}) = 8

x, - cos (x) = 0

What is the general solution for 2cos(5x)=0 ?
The general solution for 2cos(5x)=0 is x= pi/(10)+(2pin)/5 ,x=(3pi}{10}+\frac{2pin)/5