What is the general solution for 4sin(b)+sqrt(8)=0 ?

The general solution for 4sin(b)+sqrt(8)=0 is b=(5pi)/4+2pin,b=(7pi)/4+2pin

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4sin(b)+sqrt(8)=0

4 sin (b) + 8 = 0

b = \frac{5 π}{4} + 2 πn, b = \frac{7 π}{4} + 2 πn

Solution steps

4 sin (b) + 8 = 0

Simplify

4 sin (b) + 8 : 4 sin (b) + 22

4 sin (b) + 22 = 0

Move

22

to the right side

4 sin (b) = - 22

Divide both sides by

4

sin (b) = - \frac{2}{2}

General solutions for

sin (b) = - \frac{2}{2}

b = \frac{5 π}{4} + 2 πn, b = \frac{7 π}{4} + 2 πn

sin (x) = \frac{73}{83}

cos (2 B) = \frac{21}{35}

sin^{2} (x) = cos (x) - cos^{2} (x)

x, arcsin (x + y) = 0

1 + cos (π x) = sin (π x)

What is the general solution for 4sin(b)+sqrt(8)=0 ?
The general solution for 4sin(b)+sqrt(8)=0 is b=(5pi)/4+2pin,b=(7pi)/4+2pin