What is the general solution for cos(a)+1=4cos(a)+1 ?

The general solution for cos(a)+1=4cos(a)+1 is a= pi/2+2pin,a=(3pi)/2+2pin

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cos(a)+1=4cos(a)+1

cos (a) + 1 = 4 cos (a) + 1

a = \frac{π}{2} + 2 πn, a = \frac{3 π}{2} + 2 πn

Solution steps

cos (a) + 1 = 4 cos (a) + 1

Solve by substitution

cos (a) = 0

cos (a) = 0 : a = \frac{π}{2} + 2 πn, a = \frac{3 π}{2} + 2 πn

Combine all the solutions

a = \frac{π}{2} + 2 πn, a = \frac{3 π}{2} + 2 πn

6 cos (x) + 3 sin (x) = 5

(2 sin (x) - 1) cos (x) = 0

sin (2 x) + cos (x) = 0, x \leq 2 π, 0

6 sin (x) = 5 cos (x)

sin (θ) = \frac{- 3}{4}

What is the general solution for cos(a)+1=4cos(a)+1 ?
The general solution for cos(a)+1=4cos(a)+1 is a= pi/2+2pin,a=(3pi)/2+2pin