What is the general solution for sin^2(θ)-sin(θ)=2 ?

The general solution for sin^2(θ)-sin(θ)=2 is θ=(3pi)/2+2pin

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sin^2(θ)-sin(θ)=2

sin^{2} (θ) - sin (θ) = 2

θ = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (θ) - sin (θ) = 2

Solve by substitution

sin (θ) = 2, sin (θ) = - 1

sin (θ) = 2 :

No Solution

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{3 π}{2} + 2 πn

x, sin (x) cos (x) = 0

\frac{2}{3} = \frac{sin ( 13 5 ^{\circ} )}{sin ( x )}

10 = cos (x)

tan (θ) = \frac{0}{5}

3 tan (x^{2}) - 1 = 0

What is the general solution for sin^2(θ)-sin(θ)=2 ?
The general solution for sin^2(θ)-sin(θ)=2 is θ=(3pi)/2+2pin