What is the general solution for 8*cos^2(3x)+6*cos(6x)=10216 ?

The general solution for 8*cos^2(3x)+6*cos(6x)=10216 is No Solution for x\in\mathbb{R}

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8cos^2(3x)+6cos(6x)=10216

8 \cdot cos^{2} (3 x) + 6 \cdot cos (6 x) = 10216

No Solution for x \in R

Solution steps

8 cos^{2} (3 x) + 6 cos (6 x) = 10216

Subtract

10216

from both sides

8 cos^{2} (3 x) + 6 cos (6 x) - 10216 = 0

Rewrite using trig identities

- 10212 + 10 cos (6 x) = 0

Move

10212

to the right side

10 cos (6 x) = 10212

Divide both sides by

10

cos (6 x) = \frac{5106}{5}

- 1 \leq cos (x) \leq 1

No Solution for x \in R

sin (x) = \frac{48 \cdot sin ( 6 9 ^{\circ} )}{47.5}

cos (x) = \frac{8 3}{16}

x, cos^{2} (x) = 0

cos (θ) = \frac{7}{4}

sin (2 θ - \frac{π}{2}) = - 1, 0 \leq θ \leq 2 π

What is the general solution for 8*cos^2(3x)+6*cos(6x)=10216 ?
The general solution for 8*cos^2(3x)+6*cos(6x)=10216 is No Solution for x\in\mathbb{R}